Question

Consider the line y=5/7x+7. Find the equation of the line that is parallel to this line and passes through the point (-5,-2). Find the equation of the line that is perpendicular to this line and passes through the point (-5,-2).

Answer 1

Step-by-step explanation:

m=5/7

m1=m2=5/7

L;y-(-2)=5/7(x-(-5)

y+2=5/7(x+5)

7y+14=5X+25

7y-5x=11 is parallel lines

m1*m2=-1 is perpendicular lines

m2=-1*7/5

m2=-7/5

L;y+2=-7/5(x+5)

5Y+10=-7x-35

5y+7x=-45 is perpendicular lines