The volume of the stock solution needed is 2.7 L
We'll begin by listing out what was given from the question. This includes the following:
Molarity of stock solution (M₁) = 12.4 M
Volume of diluted solution (V₂) = 7.6 L
Molarity of diluted solution (M₂) = 4.4 M
The volume of the stock solution needed can be obtained as follow:
12.4 × V₁ = 4.4 × 7.6
12.4 × V₁ = 33.44
Divide both side by 12.4
V₁ = 33.44 / 12.4
Therefore, the volume of the stock solution needed is 2.7 L
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