Answer:
Approximately 26.33 m/s.
Explanation:
We can apply one of the four kinematic equations:
[tex]\displaystyle \Delta d = \frac{1}{2}\left( v_f + v_i\right)t[/tex]
Since the car slides to a stop after traveling 7.9 meters in 0.6 seconds, Δd = 7.9, t = 0.6, and v_f = 0. Substitute and solve for v_i:
[tex]\displaystyle \begin{aligned} (7.9 \text{ m}) &= \frac{1}{2}\left((0\text{ m/s}) + v_i)(0.6\text{ s}) \\ \\ v_i &=\frac{79}{3} \text{ m/s} \approx 26.33 \text{ m/s} \end{aligned}[/tex]
In conclusion, the initial velocity of the car is about 26.33 m/s.