Question

Write the equation of the line that contains the given point and the given slope. (-46,45), slope=2.5 please help and explain

Answer 1

Answer:

y = 2.5x + 160

Step-by-step explanation:

b = 45 - (2.5)*(-46)

b = 45 + 160

b = 205

Answer 2

The equation of the line is:

$y - 45 = 2.5(x + 46)$

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The equation of a line, in point-slope form, is given by:

$y - y_0 = m(x - x_0)$

In which:

• The slope is m.

• The point is $(x_0, y_0)$.

We are given:

• Slope of 2.5, thus $m = 2.5$
• Point (-46, 45), thus $x_0 = -46, y_0 = 45$.

Then:

$y - y_0 = m(x - x_0)$

$y - 45 = 2.5(x - (-46))$

$y - 45 = 2.5(x + 46)$

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