Question

The moore family recieved 23 pieces of mail on June 12. The mail consisted of afs,bills,magazines, and letters. How many ads did they recieve if they recieved three more bills than magazines, five more letters than bills and the same number of ads of magazines?

Answer 1

Answer:

b=4 bills

Step-by-step explanation:

Let

b = number of bills received

a = number of adds received  

l = number of letters received  

m = number of magazines received

The Moore family received 27 pieces of mail, consisting of bills, ads, letters, and magazines:

b + a + l + m = 27

They received 3 more ads than letters:

a = l + 3

The same number of bills as letters:

b = l

5 more magazines than ads:

m = a + 5

Plug l = b into a = l + 3, we get: a = b + 3

Plug a = b + 3 into m = a + 5, we get: m = b + 3 + 5 that is m = b + 8

Now plug l = b, a = b + 3 and m = b + 8 into b + a + l + m = 27:

b + b + 3 + b + b + 8 = 27