It can be concluded that the final velocity of the smaller ball will be 25 m/s.
The given parameters;
- mass of the larger ball, m₁ = 5 kg
- mass of the smaller ball, m₂ = 2 kg
- initial velocity of the larger ball, u₁ = 10 m/s
- initial velocity of the smaller ball, u₂ = 0
- final velocity of the larger ball, v₁ = 0
The final velocity of the smaller ball will be calculated by applying the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(5 x 10) + (2 x 0) = (5 x 0) + (2)v₂
50 + 0 = 0 + 2v₂
50 = 2v₂
v₂ = 25 m/s
Thus, it can be concluded that the final velocity of the smaller ball will be 25 m/s.
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