Answer:
a. (1,2), b. (1, 0)
Step-by-step explanation:
a.
[tex]\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\\\text{Substitute the values.}\\\frac{-3+5}{2},\frac{5+(-1)}{2}\\\text{Evaluate the numerators.}\\\frac{2}{2},\frac{4}{2}\\\text{Simplify.}\\1,2\\\text{The midpoint of (-3, 5) and (5, -1) is (1, 2).}[/tex]
b.
[tex]\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\\\text{Substitute the values.}\\\frac{-4+6}{2},\frac{-3+3}{2}\\\text{Evaluate the numerators.}\\\frac{2}{2},\frac{0}{2}\\\text{Simplify.}\\1,0\\\text{The midpoint of (-4, -3) and (6, 3) is (1, 0).}[/tex]