Question

F(x)=x^2-1
G(x)=x-1
find (f+g)(10).

Answer 1

Adding Functions

Answer:

$(f +g)(10) = 108$

Step-by-step explanation:

Before we can solve for $(f +g)(10)$, we need to know how $(f +g)(x)$ is defined.

$(f +g)(x) = f(x) +g(x) \\ (f +g)(x) = (x^2 -1) +(x -1) \\ (f +g)(x) = x^2 -1 +x -1 \\ (f +g)(x) = x^2 +x -2$

We can now solve for $(f +g)(10)$:

$(f +g)(10) = (10)^2 +(10) -2 \\ (f +g)(10) = 100 +10 -2 \\ (f +g)(10) = 108$