Question

The length of a rectangle is twice its width.
If the area of the rectangle is 128 yd?, find its perimeter.

Answer 1

Answer:

$let \: w \: be \: the \: width \: and \: l = 2w \\ area \: = 128 = (w)(2w) \\ 2{w}^{2} = 128 \\ {w}^{2} = 64 \\ w = 8 \: yd \\ l = 16 \\ perimeter \: = 2(8) + 2(16) = 48 \: yd$