Question

Can anyone help me on this? HELP NEEDED

Answer 1

Answer:

$-4\frac{4}{9} < \sqrt{16} < 4.3 < \frac{61}{14}$

Step-by-step explanation:

First off, we can simplify $\frac{61}{14}$ to around $4.3571$ and simplify $\sqrt{16}$ to $4$.

We know that $-4 \frac{4}{9}$ is the smallest number, since it's the only negative, so it has to be on the far left.

Out of the remaining three, we then know that $4$, or $\sqrt{16}$ is the next smallest.

Finally, $4.3$ (repeating) is smaller than $4.3571$, or $\frac{61}{14}$.

This gives us the order of numbers:

$-4\frac{4}{9} < \sqrt{16} < 4.3 < \frac{61}{14}$

Answer 2

Answer:

Step-by-step explanation:

sure, first of all let's just turn all of this into regular numbers ( or decimals)

61 / 14  =  4.357

  _

4.3 = 4.3333 (infinity)

-4 4/9  let's multiply -4 by 9 and then and to the numerator(4)

-4*9 =-36

-36 + 4 = -32

V 16 = 4

1. -32 < 4 < 4.3333  <  4.357

or

                                        _

2.  -4 4/9  <   V 16 <    4.3    <      61/14

any questions? please feel free to ask :D