Answer:
What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.
The mass of solute in potassium phosphate will be 6.47 g.
K3 PO4 is the formula for potassium phosphate. Adding the respective molecular masses of each component in the formula unit yields the formula mass.
Calculation of mass of solute is shown as below:
It is given that, M = 0.122 mol/L and V = 250 mL = 0.250 L
It is known the formula of moles.
M = n / V
n = M×V.
Put the value of given data in above equation.
n = 0.250 × 0.122 = 0.0305.
Now, convert moles in to gram.
Moles of potassium phosphate × gram of potassium phosphate/ 1 mol potassium phosphate = gram He.
0.0305 × 212.27 g / 1 = 6.47 g
Therefore, the mass of solute will be 6.47 g.
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