Question

Simplify the following
$( {2}^{2} + {3}^{2} - {4}^{2} ) \times ( {3}^{0} + 2)$
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Answer 1

Answer:

I

Step-by-step explanation:

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Answer 2

Arithmetic

Answer:

$-9$

Step-by-step explanation:

$2^2 = 2 \times 2 = 4$

$3^2 = 3 \times 3 = 9$

$4^2 = 4 \times 4 = 16$

$3^0 = 3 \div 3 = 1$

$(2^2 +3^2 -4^2) \times (3^0 +2) \\ (4 +9 -16) \times (1 +2) \\ -3 \times 3 \\ -9$