Scott decides to add running into an exercise routine and runs a total of 1 mile his first week he plans to double the number of miles he runs each week. a. Arithmetic or geometric. b. Recursive. c. explicit 

Respuesta :

The question is an illustration of geometric progression.

  • The recursive function is: [tex]T_n = 2T_{n-1}[/tex].
  • The explicit function is: [tex]T_n = 2^{n-1}[/tex]

From the question, we have:

[tex]T_1= 1[/tex] ---- the first week

[tex]r = 2[/tex] ---- The rate at which the distance increases each week.

When a sequence has a common ratio, the sequence is said to be a geometric sequence.

The Recursive function.

We have given that

[tex]T_1= 1[/tex] ---- the distance in the first week

The second week would be:

[tex]T_2 = r \times T_1[/tex]

For the third week, the distance would be:

[tex]T_3 = r \times T_2[/tex]

Express 2 as 3 - 1

[tex]T_3 = r \times T_{3-1}[/tex]

Replace 3 with n, to get the distance for the nth week

[tex]T_n = r \times T_{n-1}[/tex]

Substitute 2 for r

[tex]T_n = 2 \times T_{n-1}[/tex]

[tex]T_n = 2T_{n-1}[/tex]

Hence, the recursive function is: [tex]T_n = 2T_{n-1}[/tex]

Explicit function

The nth term of a geometric sequence is:

[tex]T_n = T_1 \times r^{n-1}[/tex]

Substitute values for [tex]T_1\\[/tex] and r.

[tex]T_n = 1 \times 2^{n-1}[/tex]

[tex]T_n = 2^{n-1}[/tex]

Hence, the explicit function is: [tex]T_n = 2^{n-1}[/tex]

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