An equation in slope-intercept form of the line
[tex]p=-\frac{9}{2}w+268\\[/tex]
Given :
Bill began his diet when he weighed 268 pounds.
After 4 weeks he weighed 250 pounds
Lets 'w' represents weeks and 'p' represents pounds
Using the given information ,we find two points (w,p)
Bill began his diet when he weighed 268 pounds.
when w=0 , weight in pounds =268
(0,268)
After 4 weeks he weighed 250 pounds, so point is (4,250)
Use two points to write the equation of line
Slope intercept form is y=mx+b
where m is the slope and b is the y intercept
slope formula using 2 points (0,268) and (4,250)
[tex]m=\frac{y_2-y_1}{x_2-x_1} =\frac{250-268}{4-0} =-\frac{9}{2}[/tex]
now use slope m and any one point (0,268) to write equation
[tex]y=mx+b\\y=-\frac{9}{2}x+b\\(0,268) where x=0 and y=268\\268=-\frac{9}{2}(0)+b\\\\b=268[/tex]
we know that w represents weeks and p represents pounds
The equation of the line in slope intercept form is
[tex]p=-\frac{9}{2}w+268\\[/tex]
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