The equation of a parabola is represented as: [tex]y = a(x- h)^2 + k[/tex], where (h,k) represents the vertex.
The question is incomplete, as the vertex and the required coordinates are not given. So, I will make assumptions.
Assume the vertex is (3,-5).
So, we have:
[tex]y = a(x- h)^2 + k[/tex]
[tex]y = a(x - 3)^2 - 5[/tex]
Also, assume the function passes through (0,13).
The expression becomes
[tex]13 = a(0 - 3)^2 - 5[/tex]
[tex]13 = a(- 3)^2 - 5[/tex]
[tex]13 = 9a- 5[/tex]
Collect like terms
[tex]9a = 13 + 5[/tex]
[tex]9a = 18[/tex]
Divide by 9
[tex]a = 2[/tex]
Hence, the function is:
[tex]y = a(x - 3)^2 + 5[/tex]
[tex]y = 2(x - 3)^2 + 5[/tex]
Rewrite as:
[tex]g(x) = (x - 3)^2 + 5[/tex]
See attachment for the graph of [tex]g(x) = (x - 3)^2 + 5[/tex]
From the graph, the x values span across the x-axis.
This means that the domain of g(x) is: [tex](-\infty, \infty)[/tex]
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