Question

3. On a hike you walk 5,000 m East, 3,000 m North, and 1,000 m West at a constant speed of 1 m/s. Calculate your velocity.(1 point)
A.0.44 m/s East + 0.33 m/s North

B.1.0 m/s

C.1.0 m/s East + 1.0 m/s North

D.0.55 m/s

4.You ride your bike at a constant speed of 5 ms for 300 s from your house to the mailbox. What was your acceleration for the trip?(1 point)

A.0 m/s2

B.5 m/s2

C.60 m/s2

D.300 s

Answer 1

(1) the average velocity of this motion is 0.55 m/s.

(2) the acceleration is of the trip is 0 m/s²

The given parameters;

displacement on hike = 5,000 m East, 3,000 m North and 1,000 m West.

(1) Average velocity is the ratio of the total displacement to total time of motion.

A simple sketch of the motion is given as;

                                 1000 m  

                               P --------- ↑

                                ↑            ↑ 3000 m

                                ↑            ↑

 Q|------------------------|------------|

         4000 m             1000 m

A line joining point P and Q is the resultant displacement = hypotenuse side of the right triangle.

$R^2 = 4000^2 + 3000^2\\\\R^2 = 25,000\\\\R = \sqrt{25,000,000} \\\\R = 5,000 \ m$

The total distance is calculated as;

= 5000m + 3,000m + 1,000 m

= 9,000 m

The time of this motion is calculated as;

$speed = \frac{total \ distance }{time \ of \ motion} \\\\1 = \frac{9,000}{t} \\\\t = 9,000 \ s$

The average velocity is calculated as;

$v= \frac{displacement }{t} \\\\v = \frac{5,000 \ m}{9,000 \ s} = 0.55 \ m/s$

Thus, the average velocity of this motion is 0.55 m/s.

(2) Acceleration is the change in velocity per change in time of motion,

$a = \frac{v_2-v_1}{t}$

at constant speed, v₁ = v₂, and v₂ - v₁ = 0

Thus, the acceleration is of the trip is 0 m/s²

Learn  more here: https://brainly.com/question/17375280