Question

A catapult launches a projectile with an initial velocity of 20.0 m/s at an angle of 40.0° above the horizontal.
What are the magnitudes of the horizontal and vertical components of the velocity at t = 1.10 s?

Answer 1

The vertical component of the velocity is 23.64 m/s

The horizontal component of the velocity is 15.32 m/s

The given parameters include;

initial velocity of the catapult = v = 20 m/s

angle of projection, Ф = 40 °

The vertical component of the velocity at the given time is calculated as;

$v_f_y = v_0_ysin(\theta) + gt\\\\v_f_y = 20\times sin(40) + (9.8 \times 1.1)\\\\v_f_y =12.86 + 10.78\\\\v_f_y = 23.64 \ m/s$

The horizontal component of the velocity is calculated as;

$v_x = v_0_x$

acceleration due to gravity is zero in horizontal direction;

$v_0_x = v_ocos(\theta)\\\\v_0_x = 20 \times cos(40)\\\\v_0_x = 15.32 \ m/s$

Learn more here: https://brainly.com/question/20349275