In the pair competition of Olympic figure skating, a 60-kg male skater pushes a 45-kg female skater. If the push caused the female to accelerate at 2.0 m/s, what is the acceleration of the male skater?

Respuesta :

Step-by-step explanation:

Male=60kg

female=45kg

accelerate= 2.0 m/s

solution,

Here,

a= v-u

2.0= 60-45

2.0 = 15

= 15-2.0

Accelerate = 13 m/s is a male skater .

The acceleration of the male skater will be 13 meters per second.

What is acceleration?

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities and accelerations.

Given that in the pair competition of Olympic figure skating, a 60-kg male skater pushes a 45-kg female skater.

Male=60kg

female=45kg

accelerate= 2.0 m/s

The value of the acceleration will be calculated as:-

a + m = v-u

2.0 + m= 60-45

2.0 + m  = 15

m = 15-2.0

m =13 meters per second

Therefore, the acceleration of the male skater will be 13 meters per second.

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