Question

Assume that a catcher in a professional baseball game catches a ball that has been pitched with an initial velocity of 42.0 m/s to the southeast. If the catcher uniformly brings the ball to rest in 0.00090s through a distance of 0.020 m to the southeast, what is the balls acceleration?

Answer 1

This question can be solved using the equations of motion.

The acceleration of the ball is "-44100 m/s²".

We can find out the acceleration of the ball by using the third equation of motion:

$2as = v_f^2 - v_i^2$

where,

a = acceleration = ?

s = distance covered = 0.02 m

vf = final velocity = 0 m/s

vi = initial velocity = 42 m/s

Therefore,

2a(0.02 m) = (0 m/s)² - (42 m/s)²

a = -44100 m/s²

negative sign shows deceleration

Learn more about the equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion.