The skid mark will be 25.21 m long.
From the question given above, the following data were obtained:
Initial velocity (u) = 22.0 m/s
Final velocity (v) = 0 m/s
Deceleration (a) = –9.6 m/s²
Displacement (s) =?
The displacement can be obtained as follow:
v² = u² + 2as
0² = 22² + (2 × –9.6 × s)
0 = 484 – 19.2a
Collect like terms
0 – 484 = –19.2s
–484 = –19.2s
Divide both side by –19.2
[tex]s = \frac{-484}{-19.2} \\\\[/tex]
s = 25.21 m
Therefore, the skid mark is 25.21 m long
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