Points A, B, and C are collinear and B lies between A and C
The value of BC=30
Given :
Points A, B, and C are collinear and B lies between A and C.
AC = 48, AB = 2x + 2, and BC = 3x + 6
B lies between A and C
So, AC=AB+BC
Substitute the given values and solve for x
[tex]AC=AB+BC\\48= 2x+2+3x+6\\[/tex]
Combine like terms
[tex]48=5x+8[/tex]
Subtract 8 from both sides
[tex]40=5x\\Divide \; by \; 5\\x=8[/tex]
Now find out BC by substituting 8 for x in BC
[tex]BC=ex+6\\BC=3(8)+6\\BC=30[/tex]
The value of BC=30
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