Question

Please help im being timed
A baseball is hit at an initial speed of 40 m/s at an angle of 60° above the horizontal. Find the ball’s maximum height in meters. Use g = 9.81 m/s2.
A
10.2

B
20.4

C
22.4

D
61.2

Answer 1

Answer:

7.06 m

Explanation:

• Initial velocity = 40m/s
• Angle = 60°
• g = 9.81 m/s²
• Maximum height = ?

As we know that ,

→ h = u²sin²∅/2g

→ h = 40 * 40 * sin² 60° / 2 * 9.81

→ h = 40 * 40 * √3 / 2 * 2 * 9.81

→ h = 7.06 m