Question

chứng minh: x² - 8x + 17 > 0

Answer 1

Answer: All Real Numbers

x2−8x+17>0  

x2−8x+17=0

For this equation: a=1, b=-8, c=17

1x2+−8x+17=0

x=

−b±√b2−4ac

2a

(Use quadratic formula with a=1, b=-8, c=17)

x=

−(−8)±√(−8)2−4(1)(17)

2(1)

x=

8±√−4

2

All real numbers