Question

f f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
6 – 3 – (4 + 3)2
6 – 3 – (4 – 32)
6(3) – 4 + 32
6(3) – 4 – 32

Answer 1

Subtracting Functions

Answer:

$6(3) -4 +3^2$

Step-by-step explanation:

Given:

$f(x) = 4 -x^2$

$g(x) = 6x$

Before we find the expression of $(g -f)(3)$, we must first know how $(g -f)(x)$ is defined.

$(g -f)(x) = g(x) -f(x) \\ (g -f)(x) = 6x -(4 -x^2) \\ (g -f)(x) = 6x +x^2 -4 \\ (g -f)(x) = x^2 +6x -4$

Now we can find $(g -f)(x)$.

$(g -f)(3) = (3)^2 +6(3) -4$

Answer 2

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