Question

A spray paint can with a pressure of 2.50 atm is trapped inside a burning
factory. Its initial temperature is 25°C. What is the final pressure of the can
if the fire reaches a temperature of 635°C? Assume that the volume of the
can remains constant!

Answer 1

First convert Temperatures to Kelvin scale

• 25°C=25+273=298K
• 635°C=635+273=908K

Now

• P_1=2.5atm
• T_1=298K
• T_2=908K

USING GAY LUSSAC's Law

$\\ \sf\longmapsto P_1T_2=P_2T_1$

$\\ \sf\longmapsto P_2=\dfrac{P_1T_2}{T_1}$

$\\ \sf\longmapsto P_2=\dfrac{2.5(298)}{25}$

$\\ \sf\longmapsto P_2=\dfrac{795}{25}$

$\\ \sf\longmapsto P_2=31.8atm$