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You need to make 25 ml of a 0.75 M sodium acetate solution. How much pure
sodium acetate (solid; MW=82.03 g/mol) would you use to make this solution?

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samueladesida43

The amount of pure sodium acetate that would be used to make the sodium acetate solution is 1538.06 grams

CALCULATE AMOUNT OF ACETATE IN GRAMS:

  • To calculate the amount (in grams) of sodium acetate in a solution, we must first calculate the number of moles in the solution using the following formula:

no. of moles (mol) = mass (g) ÷ molar mass (g/mol)

  • The molarity of a solution can be calculated using the formula:

  • MOLARITY = no. of moles ÷ volume

0.75 = n ÷ 25

n = 25 × 0.75

n = 18.75mol

  • Hence, the mass of sodium acetate can be calculated as follows:

mass = 18.75 × 82.03

mass = 1538.06 grams

  • Therefore, 1538.06 grams of pure sodium acetate would be used to make this solution.

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