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A speeder passes a stationary police officer at a constant speed of 45 m/s. The police officer
immediately begins pursuit with a constant acceleration of 5 m/s^2. Assuming the speeder
maintains their original velocity determine:
a) The time required for the officer to catch the speeder in seconds(Number only).
[Select ]
b) The velocity of the officer at the time of intercept in m/s (Number only).
[ Select]

Respuesta :

Answer:

a) 9

b) 45

I am not sure of the b part though :)

Explanation:

a) a= v /t  

  t= 45/5

    = 9

b) intial v= 0 t=9 s a= 5

5x 9 = 45

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