Question

A 1500-kilogram car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 meters per second to 27 meters per second in 8 seconds. What is the acceleration of the car? What is the force of the car moving forward?

Answer 1

The acceleration of the car and the force of the car moving forward are:

1. The acceleration of the car is 3.375 m/s².

2. The force moving the car is 5062.5 N

From the question given above, the following data were obtained:

Mass of car = 1500 Kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

Acceleration (a) =?

Force (F) =?

1. Determination of the acceleration

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

Acceleration (a) =?

$a = \frac{v - u}{t} \\\\a = \frac{27 - 0}{8} \\\\a = \frac{27}{8}$

a = 3.375 m/s²

Therefore, the acceleration of the car is 3.375 m/s²

2. Determination of the force moving the car.

Mass of car = 1500 Kg

Acceleration (a) = 3.375 m/s²

Force (F) =?

F = ma

F = 1500 × 3.375

F = 5062.5 N

Therefore, the force moving the car is 5062.5 N

Learn more: https://brainly.com/question/13001406