Question

5. La cabeza de un tornillo tiene un grosor de 0.548 unidades. ¿Cuál suma de fracciones decimales representa ese número?

Answer 1

The sum of decimal fractions that the value 0.548 represents is

$\frac{3}{10}+ \frac{24}{100} +\frac{8}{1000}$

Given the decimal value, it can also be expressed as the sum of decimals as shown;

$0.548 = 0.3 + 0.24 + 0.008$

0.3 is to the nearest tenth

0.24 is to the nearest hundredth

0.008 is to the nearest thousandth

Express the decimals as fractions as shown

$0.3=\frac{3}{10}\\0.24=\frac{24}{100}\\0.008=\frac{8}{1000}$

Substitute the fractions into the expression above to have:

$0.548 = \frac{3}{10}+ \frac{24}{100} +\frac{8}{1000}$

Hence the sum of decimal fractions that the value 0.548 represents is

$\frac{3}{10}+ \frac{24}{100} +\frac{8}{1000}$

Learn more here: brainly.lat/tarea/11893024