Question

Identify the maximum and minimum values of the function y = 10 cos x in the interval [-2π, 2π].

Answer if only know

Answer 1

We know that the maximum and minimum values of the function y = cos x in the interval [-2π, 2π] are 1 and -1 respectively.
 
The graph of y = 8 cos x is vertical stretch by a factor of 8 units. Therefore the graph y=cos x, = the maximum and minimum values of the function y = cos x in the interval [-2π, 2π]. So they are 8 and -8 respectively.  

max = 8,  ∈[−2π,2π]
                                                    = Solution 
min = −8.  ∈[−2π,2π]

Answer 2

The maximum value of the function (y = 10 cos x ) in the interval [-2$\pi$,2$\pi$] is 10 and the minimum value of the function (y = 10 cos x ) in the interval [-2$\pi$,2$\pi$] is -10.

Given :

• Trigonometric Function -- $\rm y = 10\;cosx$
• Interval  ---  [-2$\pi$,2$\pi$]

The following steps can be used in order to determine the maximum and minimum values of the function (y = 10 cos x) in the interval [-2π, 2π]:

Step 1 - Remember the maximum value of the graph of the function (y = cos x) in the interval [-2$\pi$,2$\pi$] is 1 and the minimum value of the graph of the function (y = cos x) in the interval [-2$\pi$,2$\pi$] is -1.

Step 2 - From the above step, it can be said that the maximum value of the function (y = 10 cos x) in the interval [-2$\pi$,2$\pi$] is 10.

Step 3 - Also from step 1, it can be said that the minimum value of the function (y = 10 cos x) in the interval [-2$\pi$,2$\pi$] is -10.

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https://brainly.com/question/21286835