Answer:
[tex]14.7\ in^{3}[/tex]
Step-by-step explanation:
Step 1
Find the volume of Cup A
we know that
The volume of a cone is equal to
[tex]V=\frac{1}{3}\pi r^{2} h[/tex]
where
r is the radius of the base of the cone
h is the height of the cone
In this problem we have
[tex]r=2/2=1\ in, h=4\ in[/tex]
substitute
[tex]V=\frac{1}{3}\pi (1)^{2} (4)[/tex]
[tex]Va=\frac{4\pi}{3}\ in^{3}[/tex]
Step 2
Find the volume of Cup B
we know that
The volume of a cylinder is equal to
[tex]V=\pi r^{2} h[/tex]
where
r is the radius of the base of the cylinder
h is the height of the cylinder
In this problem we have
[tex]r=2/2=1\ in, h=6\ in[/tex]
substitute
[tex]V=\pi (1)^{2} (6)[/tex]
[tex]Vb=6\pi\ in^{3}[/tex]
Step 3
Find the difference of volume
[tex]Vb-Va=6\pi\ in^{3}-\frac{4\pi}{3}\ in^{3}\\\\=\frac{14\pi}{3}\\\\=14.7\ in^{3}[/tex]