Respuesta :

Step-by-step explanation:

Let 8=x

[tex] {x}^{ - 4} \times {x}^{3} [/tex]

[tex] \frac{1}{ {x}^{4} } \times {x}^{2 + 1} [/tex]

[tex] \frac{1}{ {x}^{2 + 2} } \times {x}^{2} \times x[/tex]

A

[tex] \frac{1}{ {x}^{2} } \times x[/tex]

[tex] \frac{x}{ {x}^{2} } [/tex]

[tex] {x}^{ - 1} [/tex]

[tex] \frac{1}{8} [/tex]

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