Question

A store manager gathers some demographic information from the store's customers. The following chart
summarizes the age-related information they collected:
Age Number of Customers
< 20
82
20-29
94
30-39
64
40-49
76
50-59
55
96
2 60
One customer is chosen at random for a prize giveaway. (Round answers to 4 decimal places.)
a. What is the probability that the customer is at least 20 but no older than 49?
b. What is the probability that the customer is either older than 40 or younger than 20?
c. What is the probability that the customer is at least 50?

Answer 1

Using probabilities concepts, it is found that:

• a) 0.5011 = 50.11% probability that the customer is at least 20 but no older than 49.
• b) 0.6617 = 66.17% probability that the customer is either older than 40 or younger than 20.
• c) 0.3233 = 32.33% probability that the customer is at least 50.

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A probability is the number of desired outcomes divided by the number of total outcomes.

• From the chart, the total number of customers is: 82 + 94 + 64 + 76 + 55 + 96 = 467.

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Item a:

• 94 + 64 + 76 = 234 customers are at least 20 but no older than 49.
• Out of 467 customers, thus:

$p = \frac{234}{467} = 0.5011$

0.5011 = 50.11% probability that the customer is at least 20 but no older than 49.

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Item b:

• 82 are younger than 20.
• 76 + 55 + 96 = 227 are older than 40.
• 82 + 227 = 309 are either, thus:

$p = \frac{309}{467} = 0.6617$

0.6617 = 66.17% probability that the customer is either older than 40 or younger than 20.

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Item c:

• 55 + 96 = 151 are at least than 50, thus:

$p = \frac{151}{467} = 0.3233$

0.3233 = 32.33% probability that the customer is at least 50.

A similar problem is given at https://brainly.com/question/15536019