The required inequalities to solve the problem are :
c + y = 6
c + y = 610c + 20y ≤ 100
Let :
Number of shirts = c
Number of shirts = c Number of pants = y
Number of shirts = c Number of pants = y Total number of items = 6
Hence,
c + y = 6 - - - (1)
Maximum amount spent = $100
(cost of shirt × Number of shirt) + (cost of pant × number of pant) ≤ 100
(10 × c) + (20 × y) = 10c + 20y ≤ 100 - - - (2)
The required inequalities are :
c + y = 6
c + y = 610c + 20y ≤ 100
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