"13" or "more than 13" rides will make the weekly unlimited pass more cost effective. A further solution is provided below.
The given values are:
The Fare after discount will be:
= [tex]2.75\times \frac{100-5}{100}[/tex]
= [tex]2.75\times \frac{95}{100}[/tex]
= [tex]2.75\times 0.95[/tex]
= [tex]2.6125[/tex] ($)
hence,
In $32, the minimum number of rides will be:
= [tex]\frac{32}{2.6125}[/tex]
= [tex]12.24[/tex]
or,
= 13
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