Question

Find the solution to the system represented by this matrix

Answer 1

Answer:

$x=\frac{-1}{5},$

$y=\frac{2}{5},$

$z=3$

Step-by-step explanation:

Given system of equations in the form of the matrix shown below,

$A=\left[\begin{array}{ccc}1 & -2 & 0 \\ 1 & 3 & 5 \\ 1 & -1 & -1\end{array}\right] \quad B=\left[\begin{array}{c}4 \\ -1 \\ 3\end{array}\right]$

$\left[\begin{array}{ccc}1 & -2 & 0 \\ 1 & 3 & 5 \\ 1 & -1 & -1\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{c}4 \\ -1 \\ 3\end{array}\right]$

$\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\frac{1}{-10}\left[\begin{array}{ccc}2 & -6 & -4 \\ -2 & -1 & 1 \\ -10 & 5 & 5\end{array}\right]\left[\begin{array}{c}4 \\ -1 \\ 3\end{array}\right]$

$\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\frac{1}{-10}\left[\begin{array}{c}8+6-12 \\ -8+1+3 \\ -40-5+15\end{array}\right]$

$\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\frac{1}{-10}\left[\begin{array}{c}2 \\ -4 \\ -30\end{array}\right]$

$\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}\frac{2}{-10} \\ \frac{-4}{-10} \\ \frac{-30}{-10}\end{array}\right]$

$\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{c}-1 / 5 \\ 2 / 5 \\ 3\end{array}\right]$

Learn more about matrix refer:

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