The solution to the equation [tex](\frac{-3jk^3}{2k^2m^3})^3=\frac{Aj^xk^{y}}{Bm^z}[/tex] is a = -27, x =3, y = 9, B = 8k⁶ and z = 9.
Equation
An equation is an expression used to show the relationship between two or more numbers and variables.
Given the equation as shown in the question:
[tex]\frac{-3jk^3}{2k^2m^3})^3\\ \\Simplifying\ the\ equation:\\\\=\frac{-27j^3k^{9}}{8k^6m^9} \\\\Comparing \ with\ \frac{Aj^xk^{y}}{Bm^z}\ gives:\\a=-27,x=3,y=9,B=8k^6,z=9[/tex]
The solution to the equation is a = -27, x =3, y = 9, B = 8k⁶ and z = 9.
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