Question

The length of a new rectangular playing field is 7 yards longer than triple the width. If the perimeter of the rectangular playing field is 438 ​yards, what are its​ dimensions?

Answer 1

The awnser is 578 yards

Answer 2

Explanation:

L = 7+ 3W

the perimeter = 438

2(L+W) = 438

by using substitution :

2(7+3W+W) = 438

2(4W+7) = 438

4W+7 = 438/2

4W+7 = 219

4W = 219-7

4W = 212

W = 212/4 = 53

L = 7 + 3(53)

L = 7 + 159 = 166

so, the dimensions : the length = 166 yards

and the width = 53 yards