Question

Calvin owns a toy store. He can spend at most $200 on restocking cars and dolls. A doll costs $6.50, and a car costs $8.00. Let x represent the number of cars, and let y represent the number of dolls. Identify an inequality for the number of toys he can buy. Then identify the number of dolls Calvin can buy if he buys 10 cars.

8x + 6.50y ≤ 200; no more than 19 dolls
8x + 6.50y ≤ 200; no more than 18 dolls
6.50x + 8y ≤ 200; no more than 19 dolls
6.50x + 8y ≤ 200; no more than 18 dolls

Answer 1

The required inequality expression is 8x + 6.50y ≤ 200

Maximum amount he can spend = $200

Cost of doll, = $6.50

Cost of car = $ 8.00

Mathematically, the maximum amount he can spend on restocking is cars and doll is :

(Cost of cars × number of cars) + (cost of doll × number of dolls) ≤ maximum amount

8x + 6.50y ≤ 200

Hence, the required inequality expression is : 8x + 6.50y ≤ 200

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