Find the equation of this line. y= [?]x+[?]

Answer:
[tex]y=3x-4[/tex]
Step-by-step explanation:
Hi there!
Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0)
1) Determine the slope (m)
[tex]m=\displaystyle\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:
[tex]m=\displaystyle\frac{2-(-4)}{2-0}\\\\m=\displaystyle\frac{2+4}{2}\\\\m=\displaystyle\frac{6}{2}\\\\m=3[/tex]
Therefore, the slope of the line is 3. Plug this into [tex]y=mx+b[/tex]:
[tex]y=3x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=3x+b[/tex]
Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into [tex]y=3x+b[/tex]:
[tex]y=3x+(-4)\\y=3x-4[/tex]
I hope this helps!