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[tex]\displaystyle\bf\\8192 = 2^{13}~~~It~is~not~a~perfect~cube,~but~2^{12}~is~a~perfect~cube.\\\\\implies~We~have~to~divide~the~number~8192~by~2.\\\\\frac{8192}{2}=4096=2^{12}=2^{4\times3}=\big(2^4\big)^3=16^3=perfect~cube[/tex]

 

 

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