Question

7. A distribution of newly manufactured amusement park bumper cars has mean
400 pounds and standard deviation 2 pounds. A distribution of customers
on line for the bumper-car ride has mean 60 pounds and standard deviation
2 pounds. Which distribution is more spread out? Explain.

Answer 1

Using coefficient of variation, it is found that the distribution of customers  on line for the bumper-car ride is more spread out, due to the higher coefficient of variation.

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• The coefficient of variation is given by the division of the standard deviation by the mean.
• The higher the coefficient, the more spread out the distribution is.

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• For the distribution of newly manufactured amusement park bumper cars, the mean is of 400 pounds and standard deviation is of 2 pounds, thus the coefficient is $\frac{2}{400} = 0.005$
• For the distribution of customers on line for the bumper-car ride, the mean is of 60 pounds and the standard deviation is of 2 pounds, thus, the coefficient is $\frac{2}{60} = 0.0333$.
• Due to the higher coefficient, the distribution of customers on line is more spread out.

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