Total stud=11+6=17
[tex]\\ \sf\longmapsto n(A\cup B)=n(A)+n(B)-n(A\cap B)[/tex]
[tex]\\ \sf\longmapsto 17=n(A)+10-6[/tex]
[tex]\\ \sf\longmapsto n(A)=17-4[/tex]
[tex]\\ \sf\longmapsto n(A)=13[/tex]
[tex]\\ \sf\longmapsto A=13-6=7[/tex]
Question:
10 of the students in Josiah's grade like to eat meatloaf. 11 students like to eat spaghetti, and 6 students like to eat both meatloaf and spaghetti. How many students like to eat meatloaf but not spaghetti?
Answer:
Students eating meatloaf. = A
students eating sphegetti = B
A∩ B students like both
Total students =11+6=17
⟼n(A∪B)=n(A)+n(B)−n(A∩B)
⟼17=n(A)+10−6
⟼n(A)=17−4
⟼n(A)=13
⟼A= 13−6
=7