Respuesta :

Answer:

[tex]y = ln(3x + 7) [/tex]

let inverse be m :

[tex]m = ln(3x + 7 ) \\ {e}^{m} = 3x + 7 \\ {e}^{m} - 7 = 3x \\ \\ x = \frac{ {e}^{m} - 7 }{3} [/tex]

subsitute m with x :

[tex]{ \boxed{ \boxed{ {y}^{ - 1} = \frac{ {e}^{x} - 7 }{3} }}}[/tex]

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