Question

A robot used in a pharmacy picks up a medicine bottle at t=0. It accelerates at 0.25 m/s2 for 6.5 s , then travels without acceleration for 57 s and finally decelerates at -0.60 m/s2 for 2.7 s to reach the counter where the pharmacist will take the medicine from the robot.

Answer 1

The acceleration-time graph is used to show the relationship between the acceleration of a body and time.

Let:

$a \to$ acceleration

$t \to$ time

From the question, we have the following parameters:

$(a_1,t_1) = (0,0)$

$(a_2,t_2) = (0.25,6.5)$ ---- when the robot accelerates

$(a_3,t_3) = (0,57)$ ----- when the robot travels without acceleration

$(a_4,t_4) = (-0.60,2.7)$ ---- when the robot decelerates

To represent this on an acceleration time graph, we consider the following:

• When the robot accelerates, the line on the graph increases in a right upward direction
• When the robot travels without acceleration, the acceleration is represented with a horizontal line. This simply means that acceleration is 0

• When the robot decelerates, the line on the graph decreases in a right downward direction

The total time (t) spent by the robot is 66.2 seconds

This is calculated as follows:

$t = 6.5 + 57 + 2.7$

$t = 66.2$

See attachment for the acceleration time graph (not drawn to scale)

Read more about acceleration-time graph at:

https://brainly.com/question/5285428