Let other one be x
ATQ
[tex]\\ \sf\longmapsto x+\dfrac{-8}{17}=-8[/tex]
[tex]\\ \sf\longmapsto\dfrac{17x-8}{17}=-8[/tex]
[tex]\\ \sf\longmapsto 17x-8=17(-8)=-136[/tex]
[tex]\\ \sf\longmapsto 17x=-136+8[/tex]
[tex]\\ \sf\longmapsto 17x=-128[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-128}{17}[/tex]
Answer:
Step-by-step explanation:
The other number is x: