Respuesta :

Let other one be x

ATQ

[tex]\\ \sf\longmapsto x+\dfrac{-8}{17}=-8[/tex]

[tex]\\ \sf\longmapsto\dfrac{17x-8}{17}=-8[/tex]

[tex]\\ \sf\longmapsto 17x-8=17(-8)=-136[/tex]

[tex]\\ \sf\longmapsto 17x=-136+8[/tex]

[tex]\\ \sf\longmapsto 17x=-128[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-128}{17}[/tex]

Answer:

[tex]let \: the \: unknown \: = x \: and \: y \\ x + y = - 8 \\ y = \frac{ - 8}{17} \\ x - \frac{8}{17} = - 8 \\ x = - 8 + \frac{8}{17} \\ x = \frac{17 \times - 8 + 8}{17} \\ x = \frac{ - 136 + 8}{17} \\ x = \frac{ - 128}{17} \\ thank \: you[/tex]

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