(20 points)I need help please

[tex]\text{Suppose the width of the rectangle is }x\text{ cm}[/tex]
[tex]\text{then the perimeter can be expressed as}[/tex]
[tex]2(24+x)=72[/tex]
[tex]24+x=36[/tex]
[tex]x=12[/tex]
[tex]\text{Therefore the area of the rectangle is }24\cdot x=24\cdot 12=288\text{ cm}{}^2[/tex]
Answer: Solution,
length (l) = 24 cm
perimeter (p)= 74 cm
Area (A) = ?
we know,
P = 2(l + b )
74 = 2( 24 + b)
74 = 48 + 2b
2b = 74 - 48
2b = 26
b= [tex]\frac{26}{2}[/tex]
b = 13
now,
A = l*b
= 24 * 13
= 312 cm square
Therefore, the area of the rectangle is 312 cm square.