Question

What is the radius of a circle whose equation is (x + - 5)2 + (y - 3)2 = 42?
2 units
4 units
8 units
16 units

Answer 1

Answer:

Step-by-step explanation:

The equation of the form

$(x-a)^2+(y-b)^2 =r^2$

has radius r.

Now your equation is

$(x-5)^2+(y-3)^2=42$

Hence its radius is $\sqrt{42}$

Answer 2

The radius of the circle is root 42.

We have given that equation of the circle

$(x + 5)^2 + (y - 3)^2 = 42$

What is the general form of the circle?

$(x-a)^2+(y-b)^2=r^2$

here we have (a,b) as the center of the circle

r is the radius of the circle

$r^2=42$

taking square root on both sides.

$r=\sqrt{42}$

Therefore,The radius of the circle is root 42.

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