Respuesta :
Take the LCM of 12 and 16.
12,16 (2)
6,8 (2)
3,4(2)
3,2 (2)
3,1 (3)
1,1
2*2*2*2*3 = 48
Thus, 48 is the smallest number divisible by both 12 and 16.
12,16 (2)
6,8 (2)
3,4(2)
3,2 (2)
3,1 (3)
1,1
2*2*2*2*3 = 48
Thus, 48 is the smallest number divisible by both 12 and 16.